Selected quad for the lemma: end_n

Word A Word B Word C Word D Occurrence Frequency Band MI MI Band Prominent
end_n north_n part_n south_n 1,475 5 9.1014 5 false
View all documents for the selected quad

Text snippets containing the quad

ID Title Author Corrected Date of Publication (TCP Date of Publication) STC Words Pages
B24252 An explanation of Mr. Gunter's quadrant, as it is enlarged with an analemma by Richard Holland. Holland, R. (Richard), 1596-1677.; Gunter, Edmund, 1581-1626.; Prujean, Joh. (John), mathematical instrument maker. 1676 (1676) Wing H2431 4,837 18

There is 1 snippet containing the selected quad. | View lemmatised text

the hour of the night in any place of the North-latitude thus 18. Observe some Star of the Nocturnal at the Meridian in the Heavens and turn the same of the Nocturnal to the line of 12. so shall the the day of the month of the Nocturnal stand at the Hour of Night Of the Quadrat 19. TO get an Accessible Altitude First measure a distance from the Base and observe the Summitie through the Sights and see on what part or division of the Quadrat the String falleth If on 100 then is the measured distance and Altitude of the thing above your eye equal If on 50 on the farther side of the Quadrat or Vmbra recta then is your distance double to the height If on 25 on the same side then is your distance quadruple to the height For the proportion is As 100 To the parts cut by the String So is the measured distance To the height But if the String fall on 50 on the nearer side of the Quadrat or Vmbra versa then is your distance but half the height If on 25 on the same side then is your distance but one quarter of the height above your eye For the proportion is As the parts cut by the String To 100. So is the distance measured To the height 20. Hence it followeth That if the ground will permit to take a station at will then let 50 Foot Yards c. be measured and after observation of the Summitie take half the number of the parts cut by the String on the farther side for the height desired If 25 be measured then take one quarter of the parts cut for the Altitude required This is without any Arithmetical operation The reason thereof is seeing that it is as in the first As 100 To the parts cut So the distance To the height Therefore by Alternation of proportion As 100 To the distance So the parts cut To the height But seeing that the distance is ½ or ¼ of 100 therefore also the height is ½ or ¼ of the parts cut To get an Inaccessible Altitude 21. If the height be inaccessible that is where you cannot measure to the Base then must you take two Stations both in a right line with the Base of the thing and at each Station observe the Summitie noting the parts cut both on the farther side of the Quadrat and also measure the distance between the two Stations Then must you divide 10000 by each number of parts cut at each Station For the proportion is As the difference of the two Quotients Is to the distance between the Stations So is 100 To the Altitude required And to get the distance from the nearer Station to the Base of the thing the proportion is As the difference between the Quotients To the distance between the Stations So the lesser Quotient To the distance desired Of the Analemma THis containeth all the lines in the Rundle not before mentioned in the Nocturnal viz. The Inner Circle being the Meridian of the Analemma and it is divided into 360 degrees And all the streight lines drawn therein The Equinoctial is the middle of the Parallel lines and passeth through the Center of the Rundle and the two outer lines of the Parallels are the two Tropicks the rest of the Parallels are the intermediate lines of the Suns declination The Crooked lines which are drawn over the lines of Declination are the Hour lines and at each end are figured with their proper figures The Line which cutteth the lines of Declination at right Angles is the Axis and the ends thereof are the Poles of the Analemma The moveable Index fastened upon the Pin in the Center representeth these Five Points viz. The Center of the World The points of East and West and of ♈ and ♎ To Rectifie the Analemma Put the Horizon so far under the Pole thereof as the Pole of the World is elevated in the place where you are To find the Amplitude of the Sun Rectifie and observe where the Parallel of the Suns Declination meeteth with the Horizon for there it sheweth the Amplitude To find the time of Sun Riseing Rectifie and observe what Hour line meeteth with the Section of the Horizon and the Parallel of the Suns Declination and that is the hour To find the Hour of the day First observe the Altitude of the Sun with the Quadrant then Rectifie the Analemma and with your Compasses take the Altitude from the Center along in the Horizon and run the Compasses so opened perpendicular on the Horizon till the higher foot touch the Parallel of the Suns Declination and there it meeteth with the hour To get the time of Day break if any be Rectifie and take 18 degrees along in the Horizon and put one foot of the Compasses to the upper edg of the Horizon and turn the other downwards and so run them parallel till the lower foot touch the Parallel of the Suns Declination and there it meeteth with the hour To find the continuance of Twilight or Crepusculum Take the hour of Day-break from the hour of Suns rising and the difference is the time desired To find the Ascensional difference in Time Take the time of Sun rising from 6 if the Sun be in the North Declination but if the Sun have South Declination then take 6 from the time of the Suns rising and in either case you have the ascensional difference remaining Hence the length of the day and night may be found in any Latitude Which may be thus done If the Latitude Suns Declination be North then add the ascensional difference to 6 and the total is the Semidiurnal Arch and taken from 6 leaveth the Seminocturnal Arch. But if the Latitude be North and the Suns Declinasion be South then take the ascentional difference from 6 to leave the Semidiurnal Arch but add it to 6 to make the Seminocturnal Arch. To get the Declination of the Sun Rectifie the Analemma and find the Meridian Altitude of the Sun by your Quadrant and take the same Altitude from the Horizon with the Compasses and being so opened carry them parallel on the Horizon to the Meridian Circle and there the higher point meeteth with the parallel of the Suns Declination To find the Latitude of the place where you are First get the Suns Meridian Altitude and Declination as in the last above and with your Compasses take the same Altitude from the Center along the Horizon and set one foot of the Compasses being so opened in that point of the Meridian where the parallel of the Sun toucheth it on the South part and bring the Horizon to touch the other foot of the Compasses the Compasses being kept perpendicular to the Horizon then the North end of the Horizon shall shew the Poles Altitude FINIS