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end_n draw_v line_n perpendicular_a 3,095 5 14.0786 5 true
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ID Title Author Corrected Date of Publication (TCP Date of Publication) STC Words Pages
A52257 Cosmographia, or, A view of the terrestrial and cœlestial globes in a brief explanation of the principles of plain and solid geometry applied to surveying and gauging of cask : the doctrine of primum mobile : with an account of the Juilan & Gregorian calendars, and the computation of the places of the sun, moon, and fixed stars ... : to which is added an introduction unto geography / by John Newton ... Newton, John, 1622-1678. 1679 (1679) Wing N1055; ESTC R17177 190,483 519

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southern_a semicircle_n that_o be_v from_o ♎_o to_o ♈_o be_v 178_o day_n 11_o hour_n 8_o minute_n and_o 30_o second_n in_o like_a manner_n in_o the_o year_n 1596_o between_o his_o entrance_n into_o ♉_o 15._o and_o ♍_o 15_o there_o be_v day_n 185._o 17.36_o and_o in_o the_o year_n 1597_o there_o be_v day_n 185._o 17.56_o and_o to_o find_v the_o middle_a motion_n answer_v to_o day_n 186._o hour_n 18._o minute_n 51._o second_o 30_o i_o say_v as_o 365_o day_n 6_o hour_n the_o length_n of_o the_o julian_n year_n be_v to_o 360_o the_o degree_n in_o a_o circle_n so_o be_v 186_o day_n 18_o hour_n 51′_n 30″_n to_o 184_o degree_n 03′_n 56″_n in_o like_a manner_n the_o mean_a motion_n answer_v to_o 185_o day_n 17_o h._n 46′_n be_v 183_o degree_n 02′_n 09_o apparent_a motion_n from_o ♈_o to_o ♎_o 180._o 00.00_o middle_a motion_n 184._o 03.56_o their_o sum_n 364._o 03.56_o half_a sum_n be_v the_o arch._n sme_o 182._o 01.58_o in_o 1596_o from_o 15_o ♒_o to_o 15_o ♌_o there_n be_v day_n 185_o hour_n 01_o minute_n 36._o in_o 1597._o day_n 135._o hour_n 4._o 02′_n and_o the_o mean_a motion_n answer_v thereunto_o be_v 182_o d._n 30′_n 36″_n apparent_a motion_n from_o 15_o ♉_o to_o 15_o ♍_o 180._o middle_a motion_n 185._o 17._o 56._o 181._o 04.53_o half_a sum_n be_v 183._o 32._o 26_o from_o 15_o ♒_o to_o 15_o ♌_o days_n 185._o 04_o h._n 02′_n apparent_a motion_n 180._o middle_a motion_n 182._o 30._o 36_o half_a sum_n 181._o 15._o 18_o now_o then_o in_o fig._n from_o pgc._n 181._o 32._o 26_o deduct_v nkd_v 180_o the_o remainder_n be_v dc+np_n 1._o 32._o 26._o therefore_o dc_o or_o np._n 46._o 13_o who_o sine_fw-la be_v ha._n and_o from_o xpg._n 181._o 15._o 18_o deduct_v
with_o a_o angle_n conterminate_a therewith_o be_v give_v to_o find_v the_o other_o leg._n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la the_o give_a leg_n be_v mr_n with_o the_o angle_n m._n the_o leg_n pr._n be_v require_v by_o the_o 3_o rectangle_n cot_n m._n rad_n ∷_o sine_fw-la mr._n tpr_fw-la the_o give_a leg_n rp_n and_o angle_n p._n the_o leg_n mr_n be_v require_v by_o the_o 1._o rectangle_n ctp._n rad_n ∷_o sine_z rp_n tang_n mr._n case_n 5._o a_o leg_n and_o a_o angle_n conterminate_a therewith_o be_v give_v to_o find_v the_o hypotenuse_n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o leg_n mr_n and_o the_o angle_n m_o pr._n and_o the_o angle_n p_o to_z find_fw-mi mp_n by_o the_o 5._o rectangle_n t_o mr._n rad_n ∷_o choose_fw-la m._n ct_a mp_n by_o the_o 9_o rectangle_n t_o pr._n rad._n ∷_o choose_fw-la p._n ct_a mp_n case_n 6._o the_o hypotenuse_n and_o a_o leg_n give_v to_o find_v the_o contain_v angle_n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o hypotenuse_n mp_n and_o leg_n mr._n pr._n to_o find_v m._n by_o the_o 5._o rectangle_n rad._n ct_a mp_n ∷_o t_o mr._n choose_fw-la m._n by_o the_o 9_o rectangle_n rad._n ct_a mr_n ∷_o t_o pr._n choose_fw-la p._n case_n 7._o the_o hypotenuse_n and_o one_o angle_n give_v to_o find_v the_o other_o angle_n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o hypotenuse_n mp_n &_o angle_n m_o p._n to_o find_v the_o angle_n p._n m._n by_o the_o 7._o rectangle_n cot_n m._n rad_n ∷_o choose_fw-la mp_n cot_n p._n by_o the_o 7._o rectangle_n cot_n p._n rad_n ∷_o choose_fw-la mp_n cot_n m._n case_n 8._o the_o oblique_a angel_n give_v to_o find_v the_o hypotenuse_n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o angle_n at_o p_o and_o m_o to_o find_v the_o hypotenuse_n pm_n by_o the_o 7._o rectangle_n rad._n ct_v p_o ∷_o cot_n m._n choose_fw-la mp_n case_n 9_o the_o hypotenuse_n and_o a_o angle_n give_v to_o find_v the_o leg_n conterminate_v with_o the_o give_v angle_n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o hypotenuse_n pm_n angle_n p._n m._n to_o find_v pr._n mr._n by_o the_o 9_o rectangle_n ct_n pm_n rad_n ∷_o choose_fw-la p._n t_o pr._n by_o the_o 5._o rectangle_n ct_n pm_n rad_n ∷_o choose_fw-la m._n tmr_n case_n 10._o the_o hypotenuse_n and_o a_o angle_n give_v to_o find_v the_o leg_n opposite_a to_o the_o give_v angle_n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o hypotenuse_n pm_n and_o the_o angle_n m._n p._n to_o find_v pr._n mr._n by_o the_o 2._o rectangle_n rad._n s_o mp_n ∷_o s_o m._n sine_fw-la pr._n by_o the_o 4._o rectangle_n rad._n s_o mp_n ∷_o s_o p._n sine_fw-la mr_n case_n 11._o a_o leg_n and_o a_o angle_n opposite_a thereunto_o be_v give_v to_o find_v the_o hypotenuse_n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o leg_n pr._n mr._n and_o the_o angle_n m_o p_o to_n find_v the_o hypotenuse_n pm_n by_o the_o 2._o rectangle_n s_o m._n rad_n ∷_o s_z pr._n s_o mp_n by_o the_o 4._o rectangle_n s_o p._n rad_n ∷_o s_z mr._n s_o pm_n case_n 12._o the_o hypotenuse_n and_o a_o leg_n give_v to_o find_v the_o angle_n opposite_a to_o the_o give_v leg._n in_o the_o right_o angle_a spherical_a triangle_n pmr_n the_o hypotenuse_n mp_n and_o the_o leg_n mr_n be_v give_v the_o angle_n at_o p_o be_v require_v by_o the_o four_o rectangle_n sine_fw-la mp_n to_o rad_n ∷_o s_z mr._n s_o p._n the_o hypotenuse_n mp_n and_o leg_n pr._n give_v the_o angle_n m_o be_v require_v by_o the_o second_o rectangle_n smp._n rad_n ∷_o s_z pr._n s_o m._n case_n 13._o the_o angle_n and_o leg_n conterminate_v with_o it_o be_v give_v to_o find_v the_o other_o angle_n in_o the_o right_o angle_a spherical_a triangle_n pmr_n let_v there_o be_v give_v the_o angle_n m_o p_o and_o the_o leg_n mr_n pr._n to_o find_v the_o angle_n p._n m._n by_o the_o ten_o rectangle_n rad._n c_n mr_n ∷_o s_o m._n c_n p._n by_o the_o six_o rectangle_n rad._n s_o p_o ∷_o cs_n pr._n cs_n m._n case_n 14._o a_o angle_n and_o a_o leg_n opposite_a thereunto_o be_v give_v to_o find_v the_o other_o angle_n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o angle_n p_o m_o and_o the_o leg_n mr_n pr._n to_o find_v the_o angle_n m._n p._n by_o the_o 10._o rectangle_n cs_n mr._n rad_n ∷_o cs_n p._n csm._n by_o the_o 6._o rectangle_n cs_n pr._n rad_n ∷_o cs_n m._n sp._n case_n 15._o the_o oblique_a angle_n give_v to_o find_v a_o leg._n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o angle_n at_o m_n and_o p_o to_o find_v the_o leg_n mr_n and_o pr._n by_o the_o 10._o rectangle_n sm._n rad_n ∷_o cs_n p._n c_n mr._n by_o the_o 6._o rectangle_n s_o p._n rad_n ∷_o cs_n m._n cs_n pr._n case_n 16._o the_o hypotenuse_n and_o one_o leg_n give_v to_o find_v the_o other_o leg._n in_o the_o right_o angle_a spherical_a triangle_n mpr_fw-la let_v there_o be_v give_v the_o hypotenuse_n mp_n and_o the_o leg_n pr._n mr_n to_o find_v the_o leg_n mr._n pr._n by_o the_o 8._o rectangle_n cspr._n rad_n ∷_o csmp._n csmr._n csmr._fw-la rad_n ∷_o csmp._n cspr._n thus_o i_o have_v give_v you_o the_o proportion_n by_o which_o the_o 16_o case_n of_o a_o right_o angle_v spherical_a triangle_n may_v be_v resolve_v in_o which_o there_o be_v contain_v 30_o astronomical_a problem_n two_o in_o every_o case_n except_o the_o second_o and_o the_o eight_o in_o both_o which_o case_n there_o be_v but_o two_o problem_n and_o thus_o i_o have_v do_v with_o right_o angle_a spherical_a triangle_n 5._o if_o the_o angle_n at_o the_o base_a be_v both_o acute_a or_o both_o obtuse_a the_o perpendicular_a shall_v fall_v within_o the_o triangle_n but_o if_o one_o of_o the_o angle_n of_o the_o base_a be_v acute_a and_o the_o other_o obtuse_a the_o perpendicular_a shall_v fall_v without_o the_o triangle_n 6._o however_o the_o perpendicular_a fall_v it_o must_v be_v always_o opposite_a to_o a_o know_a angle_n for_o your_o better_a direction_n take_v this_o general_a rule_n from_o the_o end_n of_o a_o side_n give_v be_v adjacent_a to_o a_o angle_n give_v let_v fall_v the_o perpendicular_a as_o in_o the_o triangle_n fp_v in_o fig._n 4._o if_o there_o be_v give_v the_o side_n f_o s_o and_o the_o angle_n at_o saint_n the_o perpendicular_a by_o this_o rule_n must_v fall_v from_o p_o upon_o the_o side_n s_o p_o extend_a if_o need_v require_v but_o if_o there_o be_v give_v the_o side_n p_o saint_n and_o the_o angle_n at_o saint_n the_o perpendicular_a must_v fall_v from_o f_o upon_o the_o side_n f_o s._n 7._o to_o divide_v a_o oblique_a angle_a spherical_a triangle_n into_o two_o right_a by_o let_v fall_n a_o perpendicular_a upon_o the_o globe_n itself_o be_v not_o necessary_a because_o all_o the_o case_n may_v be_v resolve_v without_o it_o but_o in_o projection_n it_o be_v convenient_a to_o inform_v the_o fancy_n and_o see_v the_o reason_n by_o which_o it_o be_v do_v in_o projection_n do_v depend_v upon_o the_o nature_n of_o the_o globe_n i_o will_v here_o show_v it_o both_o way_n first_o upon_o the_o globe_n and_o then_o by_o projection_n a_o oblique_a angle_a spherical_a triangle_n may_v be_v divide_v into_o two_o right_a by_o let_v fall_n a_o perpendicular_a upon_o the_o globe_n itself_o in_o this_o manner_n in_o the_o oblique_a angle_a spherical_a triangle_n fp_v in_o fig._n 4._o let_v it_o be_v require_v to_o let_v fall_v a_o perpendicular_a from_o p_o upon_o the_o side_n f_n suppose_v the_o point_n p_o to_o stand_n in_o the_o zenith_n where_o the_o arch_a f_n shall_v cut_v the_o zodiac_n which_o in_o this_o figure_n be_v at_o k_o make_v a_o mark_n and_o from_o this_o point_n of_o intersection_n of_o the_o circle_n upon_o which_o the_o perpendicular_a be_v to_o fall_v with_o the_o zodiac_n reckon_v 90_o degree_n which_o suppose_v to_o be_v at_o p_o a_o thin_a plate_n of_o brass_n with_o a_o nut_n at_o one_o end_n thereof_o whereby_o to_o fasten_v it_o to_o the_o meridian_n as_o you_o do_v the_o quadrant_n of_o altitude_n be_v graduate_v as_o that_o be_v but_o of_o a_o large_a extent_n for_o that_o a_o quadrant_n in_o this_o case_n will_v not_o suffice_v be_v fasten_v at_o p_o and_o turn_v about_o till_o it_o cut_v the_o point_n l_o in_o the_o zodiac_n will_v describe_v upon_o the_o globe_n the_o arch_n of_o a_o great_a circle_n pel_n intersect_v the_o side_n f_o s_o at_o right_a angle_n in_o the_o point_n e_o