Selected quad for the lemma: end_n

Word A	Word B	Word C	Word D	Occurrence	Frequency Band	MI	MI Band	Prominent
end_n	draw_v	equal_a	line_n	2,859	5	9.5591	5	true

Text snippets containing the quad

ID	Title	Author	Corrected Date of Publication (TCP Date of Publication)	STC	Words	Pages
A33553	Cockers arithmetick being a plain and familiar method suitable to the meanest capacity for the full understanding of that incomparable art as it is now taught by the ablest school-masters in city and countrey / composed by Edward Cocker ... ; perused and published by John Hawkins ...	Cocker, Edward, 1631-1675.; Hawkins, John, 17th cent.	1678 (1678)	Wing C4819; ESTC R8482	104,626	348

of three also by 〈◊〉 things of 〈…〉 are reduced to another 〈…〉 any Number of Integers by the price of the Integer the Product will discover the price of the Quantity or Number of Int●gers given In a R●ctangular Solid if you multiply the bred●h of the base by the depth and that Product by the length this last Product will discover the Solidity or content of the same Solid Some Questions proper to this Rule may be these following Quest. 1. What is the content of a square piece of ground whose length is 28 perches and breadth 13 perches Answer 364 square perches for multiplying 28 the length by 13 the breadth the Product is so much Quest. 2. There is a square battail whose Flank is 47 men and the files 19 deep what Number of men doth that battail contain Facit 893 for multiplying 47 by 19 the Product is 893. Quest. 3. If any one thing cost 4 shillings what shall 9 such things cost Answer 36 shillings for multiplying 4 by 9 the Product is 36. Quest. 4. If a piece of Money or Merchandize be worth or cost 7 shillings what shall 19 such pieces of Money or Merchandize cost Facit 133 shillings which is equal to 6 l. 13 s. Quest. 5. If a Souldier or Servant get or spend 14 s. per moneth what is the Wages or Charges of 49 Souldiers or Servants for the same time multiply 49 by 14 the Product is 686 s. for the Answer Quest. 6. If in a day there are 24 hours how many hours are there in a year accounting 365 dayes to constitute the year Facit 8760 hours to which if you add the 6 hours over and above 365 dayes as there is in a year then it will be 8766 hours now if you multiply this 8766 by 60 the Number of Minutes in an hour it will produce 525960 for the Number of Minuts in a Year CHAP. VII Of Division of whole Numbers 1. DIVISION is the Separation or Parting of any Number or Quantity given into any parts assigned Or to find how often one Number is Contained in another Or from any two Numbers given to find a third that shall consist of so many Units as the one of those two given Numbers is Comprehended or contained in the other 2. Division hath three Parts or Numbers Remarkable viz. First the Dividend Secondly the Divisor and Thirdly the Quotient The Dividend is the Number given to be Parted or Divided The Divisor is the Number given by which the Dividend is divided Or it is the Number which sheweth how many parts the Dividend is to be divided into And the Quotient is the Number Produced by the Division of the two given Numbers the one by the other So 12 being given to be divided by 3 or into three equal parts the Quotient will be 4 for 3 is con●ained in 12 four times where 12 is the Dividend and 3 is the Divisor and 4 is the Quotient 3. In Division set down your Dividend and draw a Crooked line at each end of it and before the line at the left hand place the Divisor and behind that on the right hand place the figures of the Quotient as in the margent where it is required to divide 12 by 3 First I set down 12 the Dividend and on each side of it do I draw a crooked line and before that on the left hand do I place 3 the Divisor then do I seek how often 3 is contained in 12 and because I find it 4 times I put 4 behind the Crooked line on the Right hand of the Dividend denoting the Quotient 4. But if the Divisor being a single Figure the Dividend consisteth of two or more places then having placed them for the work as is before directed put a point under the first Figure on the left hand of the Dividend provided it be bigger then or equal to the Divisor but if it be lesser then the Divisor then put a point under the second Figure from the left hand of the Dividend which Figures as far as the point goeth from the left hand are to be Reckoned by themselves as if they had no dependance upon the other part of the Dividend and for distinction sake may be called the Dividual then ask how often the Divisor is contained in the Dividual placing the answer in the Quotient then multiply the Divisor by the Figure that you placed in the Quotient and set the product thereof under the Dividual then draw a line under that product and Subtract the said Product from the Dividual placing the Remainder under the said line then put a point under the next figure in the Dividend on the Right hand of that which you put the point before and draw it down placing it on the Right hand of the Remainder which you found by Subtraction which Remainder with the said Figure annexed before it shall be a new dividual then seek again how often the divisor is contained in this new dividual and put the Answer in the Quotient on the Right hand of the Figure there before then multiply the divisor by the last Figure that you put in the Quotient and subscribe the Product under the dividual and make Subtraction and to the Remainder draw down the next Figure from the grand dividend having first put a point under it and put it on the right hand of the Remainder for a new dividual as before c. Observing this general Rule in all kind of Division first to seek how often the divisor is contained in the dividual then having put the answer in the quotient multiply the Divisor thereby and Subtract the Product from the dividual An Example or two will make the Rule plain Let it be Required to divide 2184 by 6 I dispose of the Numbers given as is before directed and as you see in the margent in order to the work then because 6 the divisor is more then 2 the first Figure of the dividend I put a point under 1 the second Figure which make the 21 for the Dividual then do I ask how often 6 the divisor is contained in 21 and because I cannot have it more then 3 times I put 3 in the Quotient and thereby do I multiply the divisor 6 and the product is 18 which I set in order under the dividual and Subtract it therefrom and the Remainder 3 I place in order under the line as you see in the Margent Then do I make a point under the next Figure of the dividend being 8 and draw it down placing it before the Remainder 3 So have I 38 for a new dividual then do I seek how often 6 is contained in 38 and because I cannot have more than 6 times I put 6 in the quotient and thereby do I multiply the divisor 6 and the product 36 I put under the dividual 38 and Subtract it therefrom and the remainder 2 I put under the line as you see in the Margent Then do I put a point under the