Selected quad for the lemma: day_n

Word A	Word B	Word C	Word D	Occurrence	Frequency Band	MI	MI Band	Prominent
day_n	friday_n	thursday_n	wednesday_n	6,160	5	12.4937	5	false

Text snippets containing the quad

ID	Title	Author	Corrected Date of Publication (TCP Date of Publication)	STC	Words	Pages
A77649	The description and use of the carpenters-rule: together with the use of the line of numbers (inscribed thereon) in arithmetick and geometry. And the application thereof to the measuring of superficies and solids, gaging of vessels, military orders, interest and annuities: with tables of reduction, &c. : To which is added, the use of a (portable) geometrical sun-dial, with a nocturnal on the backside, for the exact and ready finding the hour of the day and night: and other mathematical conclusions. Also of a universal-dial for the use of seamen or others. With the use of a sliding or glasiers-rule and Mr. White's rule for solid measure. / Collected and fitted to the meanest capacity by J. Browne.	Brown, John, philomath.; Gaywood, Richard, fl. 1650-1680.	1667 (1667)	Wing B5039D; ESTC R173095	73,644	256

quadrat as on a quadrant you may then move the pin to the hole at the other end of the horizontal line and you shall see that defect to be supplyed Note lastly that by heights we speak only of perpendicular or upright heights and in distances only of levels or horizontals PROB. 5. How to find unaccessable heights by the quadrat at two Observations If the place which is to be measured cannot be approached unto then work thus to find both height and distance first make choice of a place where looking up I find the thred to fall on 50 in the quadrat then the distance will be equal to the height Then make a mark at that Station and go directly backward in a right line with the former distance and make choice of a second Station where the thred may fall on 25 parts of right shadow then this second Station is double to the height and also to the distance departed from the first Station and the half therefore is the height and first distance But if it be so you cannot come to take such a height as 50 and 25 then take as you may as suppose one be at 25 and the other at 20 and suppose the height to be 100. I find that As 25 the parts cut are to 50 the side of the quadrat so is 100 the supposed height unto 200 the distance And as 20 the second Station to 50 the side of the quadrat so is 100 the supposed height unto 250 the second distance wherefore the difference between the Stations should seem to be 50 then if in measuring you find it to be either more or less then this proportion doth hold as from the supposed difference to the measured difference so from the supposed height to the true height and from the supposed distance to the true distance And now suppose the difference between the two Stations were found to be 30 by measuring Then as 50 the supposed difference to 30 the true difference so is 100 the supposed height to 60 the true height And 200 the supposed distance to 120 the true and 250 at the second Station unto 150 the distance the like reason holdeth in all other examples of this kind and if an Index with sights were fitted to the Centre it might serve for all other horizontal distances by the same reason The Vse of the Almanack PROB. 6. Having the Day of the Week to find the Day of the Month for ever First find what day of the Week the first of January is on which is thus done First find the Dominical Letter for the last Leap-year set down in the Almanack the next letter is for the next year following and so till you come to the year you look for And note every Leap-year hath two Dominical letters viz. the next before it till the 24 of February and that over it for the remainder of the year Having found it reckon from A either backwards or forwards always calling A Sunday you shall find what day is the first of January Example For the year 1656 F is the Dominical Letter therefore say A Sunday G Monday F Tuesday and that is the first of January and then make use of that thus On the first Tuesday in the beginning of February I would know the day of the Month Among the Months look for 12 which is for February reckoning from March which is always the first Month and right under ●● you have 5 for the fifth day being the first Tuesday in February and 12 19 26 for the other Tuesdays in February But now for the other Months after March you must say Wednesday the reason is because February hath 29 days and the Leap-year two Dominical Letters viz. F. and E. then reckon from E to A and it falls on Wednesday which use thus in the year 1656 and all other Leap-years As in the beginning of August on Thursday what day of the Month is it August is the sixth Month look for 6 among the Months and right under it you have 6 which is Wednesday therefore 7 is Thursday and the first Thursday in August But now for 1657. I find that Thursday is the first of January saying thus A Sunday B Saturday C Friday D Thursday And so it is all the year long in all the Months for having found the Moneth all the days right under are Thursdays and then reckon onwards or backwards for any other of the Week-days and you have your desire for any yearpast present or to come PROB. 7. To find the Epact and by that the Moons age any day of the Month. On the Leap-year you have it set down in the Almanack for the next year add 11. and you have your desire And for the next year adde 11 to that and so to the next leap-year But if by so adding it exceed 30 then take away 30 and the remain is the Epact Having the Epact add to it the day of the Month and the number of the Month from March also including both the Moneths and if they come not to 30 that is the Moons age but if they exceed 30 and the Month hath 31 days then Substract 30 and the remain is the age but if the month have but 30 days then substract but 29 and the remainder is the age of the Moon required Example In July 1656. on the 20 day the Epact is 14. then 14.20 and 5 added is 39. from which take 30 rest 9 days old on the 20 of July 1656. the Moons age sought for PROB. 8. To find the hour of the day Having found the day of the month by the Almanack you must find the mark or the space between two marks in the Kalender representing that day which do thus Look for the first letter or name of the month in the Kalender according to the time of the year then reckon from thence to the day you are in either by 5 10 15 20 25 30 31 if the parts are so divided as in small Instruments they cannot well be more but if you have single days every fifth and tenth is known from the rest by a longer stroke and the last day by the longest stroke Well having found the day or the place between two strokes representing it lay a thred from the centre over that day or for want of a thred stick a ●in in the centre and cause the shadow to fall upon the day and then observe on which or between which of the 25 or 19 lines the thred cuts the 12 of clock line for on that line must you look for the hour all that day Before I come to example I shall hint a plain word of the reason of this which I find some to marvel at The hour of the day in this and in most Instrumental-Dials is given by the Suns height now all men know the Sun is not so high in Winter as in Summer therefore the Summer hour lines will not serve the Winter and also all men know