suns oblique descension If the suns declination had been South you must then substract To find the sun rising and setting the length of the day and night To know the sun rising look in the second operation where is the ascensional difference converted into time which is 1 hour 50 m. that take from 6 a clock which will be the remainder 4.10 that is to say at 4 a clock ten min. after the sun will rise which double will be 8 h. 20 m. the length of the night To find the sun setting adde 1 h. 50 m. to 6 a clock and it will be 7 a clock 50 m. after which being doubled is 15 h. 40 m. the length of the day The Illustrated operations stands thus The suns declination North 20 d. 14 m. given d. m. The elevation of the Pole is 51 d. 32 m. given d. m. The suns almicanter is 49 d. 00 m. given d. m. The suns meridian height is 58.42 The suns place in Gemini 00.00 The suns amplitude is 33.47 The suns ascensional difference is 27.38 The same converted into time is hour 1.50 The suns almicanter at 6 a clock is 15.43 The difference of the almicanter is 28.56 The suns almicanter when he is East and West 26.13 The difference of the almicanter given 49 is 18 14 The suns azimuth at 6 a clock 12.56 The suns azimuth easterly 36.52 The degrees the sun swerved from 6 to East 17.01 The same converted into time is hour 1.08 The degrees the sun swerved from 6 to the time of observation is 55.49 The same converted into time is houres 3.43 The sun rising is at houres 4.10 The sun sets at houres 7.50 The length of the day is houres 15.40 The length of the night is houres 8.20 The sun at East houres 7.8 The sun at the point of East at houres 7.8 The hour of the day is 9 a clock 43 min. after houres 9.43 The suns right ascension is 51.48 The suns ascensional difference is 27.38 The suns oblique ascension is 30.10 The suns oblique descension is 85.26 The suns semidiurnal arch is 117.38 The suns diurnal arch is 235.16 How to calculate the Eclipse both Solar and Lunar for any place assigned for any time past present or to come IT is required to know if the Moon will be Eclipsed in February 1663 and if she be the quantity and duration Place assigned Calculated for the Town of Litterworth in Leicestershire whose Latitude is 52 deg 36 min. and the Meridian differs from London 4 minutes To know if the Moon will be Eclipsed that moneth and year first I find the opposition of the Sun and Moon that time as thus The middle motion of ☽ Time given s d. m. se s d. m se 1601 9.19.58.34 0.7.33.29 60 0 00.26.5â— 1.10.41.12 2 11.29.31.20 8.18.46.5 February 01.00.33.18 1.18.28 6 The middle motion of ☉ 10.20.30.08 11.25.28.52 Mid. motion of ☽ substr 11. â—5 28.52  Distance of ☽ from ☉ 10 25.0â—.16  Semicircle substract 6.  Dist of ☽ from ☠of ☉ 4.25.1.16  This distance reduced into time will be the true opposition of the Sun and Moon according to there middle motion as viz. The distance of the Moon from opposition of the Sun is So that the mean opposition of the Sun and Moon in that year and moneth will happen 11 day 21 houres 26 min. 13 seconds p.m. To find the true opposition of the Sun and Moon I calculate to the time of the mean opposition the true place of the Sun and Moon as viz.  ☉ longit ☉ Apogaeo ☽ longit ☽ Apogaeo Time given s d. m. se s d. m. se s d. m. se s d. m. se 1601 9â—â—9 58.34 3.5.43.28 0.7.33.29 7.19.00.30 60 00.00.26.56 1.1.38 1.10.41.12 9.11.34.42 2 11.29.31.20 2.4 8.18.46.5 2.21 19.49 February 1.00.33.18 5 1.18.28.6 0.03.27.13 dayes 11 00. â—0 50.32 2 4.24.56.25 1.13.32 houres 21 51.45  0.11.31.46 5.51 minutes 26 1.4  14.16 7 seconds 13   7 1 Middle motion of ☉ â—1 02.13.29 3.6.47.17 5. â—2 11.26 7.25.41.45 Apogaeon substract 3.6.47.17  7.25.41.45  The Anomilie of ☉ 7.25.26.12  9.06.29 4â— The Anomile of ☽ The mid motion of ☉ 11.2.13.29   The Equation added 1.42.39    The Suns place 11.3.56.05    The Moons place 5.7.6.26    The difference of Sun and Moons places I divide by the hourly motion of the Moon from the Sun and remainder will be the intervall of time that is to say the time between the mean and true opposition of the Sun and Moon 6 hours 27 min. 13 sec and in regard the Moons place exceeds the Suns place in opposition I substract the interval of time from the mean opposition as viz. The mean opposition in Anno 1663 in Febr. is 11 dayes 2 houres 30 min. 13 seconds out of which substract the interval of time 6 houres 27 min. 13 sec and remainder is 11 dayes 15 houres 3 minutes 00 sec with which corrected time I compute and examine the Sun and Moons places for the true opposition as viz.  Longit. of ☉ s d. m. h Longit. of ☽ s d. m. h.  Mid. motion of ☉ 11.1.57.14 4.28.41.3 Mid. mo of ☽ AphelioÌ„ of ☉ subst 3.6.57.17 7 26.30.58 Aph. of ☽ sub Anomile of ☉ 7 2459.5â— 9.2.2.10 Anomile of ☽ Aequation of ☉ ad 0.01.41.47 0 04.57.58 Aequ of ☽ ad Anom of ☉ coaeq 7.25.49.42 9.4.29 50 An. of ☽ coaeq True place of ☉ ♓ 03.39.01 â™ 3.39.1 Tru place of ☽ I conclude in the aforesaid year moneth day hour minute The Sun and Moon will be in opposition for the Suns true place will be Pisces 3 deg 39 min. 1 sec and the Moons true place will be Virgo 13 deg 39 min. 1 sec To find if the Moon will be eclipsed or not If at any time the mean ful Moon her place be distant from either of her nodes less than 15 degrees 12 minutes either according or contrary to the Succession of the Signs that full Moon will suffer an eclipse Example at the time of the middle of the full Moon before mentioned in Febr. 1663. the 11 day 21 hour 30 min. 13 sec the middle place of the Moon is 5 s 7 d. 6 m. 26 se and her node ascending is 5.1.26.22 So that between the Moons place and her node is but 5 deg 40 min. 4 sec So I conclude that ful Moon wil be eclipsed The apparent time to be found I substract the Aequation of civil dayes 11 houres 11 min. from the true opposition the residue will be the apparent time 14 houres 52 min. The horizontal parallex of the ☉ 2 m. 21 se The horizontal parallex of the ☽ 57.53 The hourly motion of the ☉ 2.31 The hourly motion of the ☽ 33.15 The semidiameter of the ☉ 16.38 The semidiameter of the ☽ 16.11 The appatent semidiameter of the Earths shadow is 43.36 The hourly motion of the ☉ from the ☽ 30 44 To
Speculum Perspicuum Vranicum OR A GLASSE Wherein you may behold The Revolution of the YEAR of our LORD CHRIST M.DX LIII Being the first after Bissextile or Leap-year SHEWING All the notable Aspects of the PLANETS with the MOON and among themselves With the true place of the Sun Moon In Signes Degrees and Minutes For every DAY in the YEAR And true place of the other Planets every Fift day Unto which are added some Astrological Predictions gathered from the Quarterly REVOLUTIONS of this year 1653 Calculated for the Meridian of LONDON Differs from the Meridian of Litterworth 4 Minutes Whose Pole-artick is elevated above the Horizon 51 degrees 32 minutes North latitude By THO. JACKSON Mathemat London Printed by E. Cotes for the Company of STATIONERS 1653. Vulgar notes according to the Julian account used here in England for this year 1653. The Golden Number  1 The Dominical Letter  B The Circle of the Sun  10 The Roman Indiction  6 The Number of Direction  20 The Epact  11 Shrove Sunday February 20 Septuagesima Febr. 6 Sexagesima Febr. 13 Quinquagesima Febr. 20 Quadragesima Febr. 27 Easter day Aprill 10 Rogation Sunday May 15 Ascension day May 19 Whitsunday May 29 Trinity Sunday Jun. 5 Advent Sunday Novemb. 27 〈◊〉 Term beginneth the 24 day of January and endeth the 12 day of February Easter Term beginneth the 27 of Aprill and endeth the 23 day of May. Trinity Term beginneth the 5 of June and endeth the 29 day Michaelmas Term beginneth the 24 day of October and endeth the 28 day of November The names and Characters of the 12 Signs of the Zodiack with a description of what part or member of the body each Sign governeth ♈ Aries Head and Face ♉ Taurus Neck and throat ♊ Gemini Armes Shoul ♋ Cancer Brest Stomach ♌ Leo Heart and Back ♠Virgo Bowels and Belly ♎ Libra Reins and Loines ♠Scorpio Secret Members ♠Sagittarius Thighs ♑ Capricornus Knees ♒ Aquarius Legs ♓ Pisces Feet Names and Characters of the 7 Planets with the Head and Tail of the Dragon ♄ Saturne ♃ Jupiter ♂ Mars ☉ Sol. ♀ Venus ☿ Mercury ☽ Luna ☊ Dragons Head ☋ Dragons Tail A Table of the Aspects  s. d.  ☌ Conjunction 0 0 Novilunium SS Semisextile 1 0  ⚹ Sextile 2 0 Corniculata Q Quintile 2 12  □ Quartile 3 0 Semiplena Td Tridecile 3 18  △ Trine 4 0 Gibbosa Bq Biquintile 4 24  ☠Opposition 6 0 Plenilunium A brief description of the particular things contained in this Almanack examplary IN this Almanack the twelve moneths are contained in 12 pages each page is divided into 8 Columnes In the First is placed the dayes of the moneth The second the dayes of the week The third containeth the fixed and movable spheares the beginnings and endings of the Termes the Aspects of the Planets with the Moon and mutually with themselves and the Moon in her Apogaeon Perigaeon The fourth sheweth the place of the Moon in signs degrees and minutes The fifth sheweth the place of the Sun in signs degrees and minutes The sixth sheweth the places of the Planets every fift day at noon The seventh sheweth the time of Sun rising every day in the moneth The eighth sheweth the time of Sun setting every day in the moneth Example The 19 day of Jan. being Wednesday Saturne is in Biquintile of Venus or an aspect of distance 4 signs 24 degrees on the 15 day Jupiter is Semisextile to Venus in the 9 day the Moon is in her Apogaeon and the 31 of Jan. Saturne is in Conjunction with the Moon the Moons place is 2 degr 18. min. in Leo place of the Sun is 22 degr 23 min. in Aquarius Saturn is that day 8 degrees 28 min. in Leo. How to find the true place of any of the Planets for any day that be intermediated by taking the difference betwixt the two dayes before and after the time assigned Example I would know the true place of Jupiter the 6 day of Jan. I find Jupiter on the 2 day to be 24 day 14 min. of ♑ and on the 7 day I find him in 25 day 24 m. of ♑ direct the difference is 1 day 10 min. to find his true place on the 6 day then say by the rule of 3. if 4 daies motion give 70 min. what shall 3 daies motion give multiply and divide and you shall finde 52 min. 30 sec the which adde to 24 d. 14 min. and it will be 25 d. 6 min. 30 sec the true place of Jupiter on the 6 day of Jan. The like may be said for any other time and for any other Planet Behold the work January hath xxxj dayes Full Moon 3 day 17. min. past 5 afternoon Sun rising Sun setting Last quarter 11 day 25. min. past 7 afternoon New Moon 19 day 7 min. past 6 before noon First quarter 25 day 12 min. past 11 at night MD WD Mutuall aspect ☽ place ☉ pla Planet places H.M. H.M. 1 a New year ♊ 24 33 21 52 ♄ 10 52 ♌ 8 2 3 57 2 B  ♋ 8 2 22 54 ♃ 24 14 ♑ 8 0 4 0 3 c ☌ ♃ ☉ 21 16 23 55 ♂ 2 57 ♠7 57 4 3 4 d ☽ with ♄ ♌ 4 14 24 56 ♀ 12 44 ♠7 56 4 4 5 e Simeon 16 55 25 58 ☿ 14 46 ♒ 7 55 4 5 6 f Twelfth day 29 17 26 59 ♄ 10 48 ♌ 7 54 4 6 7 g □ ♀ ☽ ♠11 25 28 0 ♃ 25 24 ♑ 7 53 4 7 8 a ☽ ☋ 23 21 29 1 ♂ 5 36 ♠7 52 4 8 9 B ☽ Apogeon ♎ 5 10 ♒ 2 ♀ 19 55 ♠7 51 4 9 10 c ☉ in ♒ 16 52 1 3 ☿ 17 56 ♒ 7 50 4 10 11 d □ ♄ ☽ 28 43 2 4 ♄ 10 6 ♌ 7 49 4 11 12 e □ ☿ ☽ ♠10 39 3 6 ♃ 26 35 ♑ 7 47 4 13 13 f Hillarie 22 46 4 7 ♂ 8 10 ♠7 46 4 14 14 g △ ♄ ☽ ♠5 16 8 8 ♀ 25 15 ♠7 45 4 15 15 a SS ♃ ♀ 18 7 6 9 ☿ 17 13 ♒ 7 44 4 16 16 B ⚹ ♂ ☽ ♑ 1 23 7 10 ♄ 9 41 ♌ 7 42 4 18 17 c ☽ with ♃ 15 4 8 11 ♃ 27 45 ♑ 7 41 4 19 18 d ☠♄ ☉ 29 6 9 12 ♂ 10 39 ♠7 39 4 21 19 e Bq ♄ ♀ ♒ 13 32 10 13 ♀ 1 15 ♑ 7 38 4 22 20 f △ ♂ ☽ 28 4 11 14 ☿ 12 26 ♒ 7 36 4 24 21 g  ♓ 12 46 12 14 ♄ 9 17 ♌ 7 34 4 26 22 a ☽ perigri 27 20 13 15 ♃ 28 55 ♑ 7 32 4 28 23 B  ♈ 11 50 14 16 ♂ 13 3 ♠7 31 4 29 24 c Term begin 26 12 15 17 ♀ 7 17 ♑ 7 30 4 30 25 d ☠♂ ☽ ♉ 10 18 16 18 ☿ 6 28 ♒ 7 28 4 32 26 e △
uberem proventum frugura item affluentem liberalem vitem Yet I see more happiness portended by the Moon her application to the two fortunes to wit the Lord of the Ascendent and his Lady which is Venus by name for the Moon is in conjunction with Jupiter on March 15 day at 2 a clock in the morning Venus with the Moon on the 17 day at 5 in the morning so that the first Planet the Moon applyes to after the Suns vernal ingress is Jupiter the Lord of the Ascendent next Venus then Mercury see what Origanus saith in such a matter In anni quarturum revolutionibus aut thematibus lunationum si luna sive firma c. potens sit in angulo vel succedente domo dignitatibus sive debilis cadens extra dignitates applicuerit benefico alicui planeti Jovi vel Veneri significabitur status populi fortunatus quo lucra eidem accrescent abundabunt necessariae vigebitque si applicuerit Jovi justitia pax libertas si Veneri erit hilaritas gaudium frequentia connubiorum In the Revolutions of the year and of the quarterly Ingresses or in the Theams of the several Lunations if the Moon whether she be strong and potent in an Angle or succedent house and in her own dignities or if she be in weak and cadent without her dignities and shall apply to any benevolent Planet viz. Jupiter or Venus it signifieth the state and condition of the people to be fortunate whereby they shall get wealth and have abundance of all necessaries and if this application be to Jupiter justice peace and liberty shall flourish If to Venus there shall be mirth joy and many mariages these are significations of double joys but the Eclipse of the Sun happening in the year 1652. 29 day of March will single the joys Jupiter with Venus doth signifie Agunt quidem juxta naturam fortioris in themate in genere vero serenitatem afferunt in aqueis vero locis mites lenes pluvias hoc certius si lunae testimonium radio vel ☌ accesserit A Table of the altitude of the Sun in the beginning of each Sign at all houres of the day calculated for 51 degrees 30 minutes North latitude Bef noon Aft. noon ♋ ♊ ♌ ♉ ♠♈ ♎ ♓ â™ â™’ ♠♑ d. m. d. m. d. m. d. m. d. m. d. m. d m. 12 62.00 58.20 50.0 38.30 27.6 18.20 15.10 11 1 59.44 56.30 48.12 36.56 25.42 17.10 13.58 10 2 53.45 50.45 43.20 32.38 21.53 13 40 10.30 9 3 45.30 43.10 36.10 26.8 15.59 8.18 5.20 8 4 36.40 34.12 27.30 18.8 8.35 1.17  7 5 27.16 25 00 18.20 9.21 0 6   6 6 18.10 15.46 9.5     5 7 9.36 7.4      4 8 1.39       You may behold in this Table that when the Suns place is in the first point of Cancer his Meridian height will be 62 degrees in Gemini is 58 deg 28 min. in Leo is the same degrees and minutes Suppose that when the Sun is in the first point of Aries or Libra and you find the height of the Sun taken by the quadrant to be 38 deg 30 min. and you would desire to know what a clock it is at that time look in the foregoing Table under the Signs Aries and Libra and you will find in the column under the title before and after noon to be 12. then you may conclude it is high noon Had it been that the Sun was but 36 deg 56 min. high that day then you may conclude to be a 11 of the clock if it be in the aforenoon if it be in the afternoon it is 1 a clock Suppose you had observed the Sun to be 26 degrees and 8 min. high in the same day then it is 9 of the clock if your observation be in the morning but if it be in the afternoon then it is 3 a clock and so with the rest At any time when the Sun is far remote from the first point of any Sign take the proportional part and the like for your altitude taken when it will not concur with the altitude in the Table so you will find the Suns altitude above the horizon at any time A Table of the Azimuth of the Sun in the beginning of each Sign for all houres of the day for the latitude of 51 deg 13 min. Bef no. Afr. no. 11 1 10 2 9 3 8 4 7 5 6 6 5 7 4 8 Signes d. m. d. m. d. m. d. m. d. m. d. m. d. m. d. m. ♋ 61.41 38.00 22.00 8.5.0 3. n. 20 14.40 25.30 37 0◠♌ ♊ 63.52 41.30 24.45 10.5.4 1.00 12.12 23.25  ♠♉ 67.10 47.30 31.2 17.00 4.3 6.52 18.12  ♎ ♈ 70.00 53.25 37.56 24.5 11.22    ♠♓ 72.30 58.00 43.40 30.25     ♠♒ 74.20 60.55 47.49 35.00     ♑ 75.2 62.1 49.3      When the Sun is in the first point in Cancer aâ— 9 a clock before noon or 3 a clock in the after noon it is required the Suns Azimuth which is 22 degr 00 min. in the same houres in Leo and Gemini it is 24 deg 45. min. as in like manner with the rest A Table of the Suns declination for every degree of the Ecliptique degrees ♎ ♈ ♠♉ ♠♊ degrees d. m d. m. d. m. 1 0.24 12.00 20.26 29 2 0.48 12.13 20.39 28 3 1.2 12.33 20.49 27 4 1.35 12.54 21.1 26 5 2.10 13.13 21.12 25 6 2.23 13.34 21.23 24 7 2.47 13.54 21.43 23 8 3.11 14.13 21.52 22 9 3.35 14.33 22.2 21 10 3.58 14.52 22.10 20 11 4.23 15.11 22.18 19 12 4.45 15.29 22.26 18 13 5.9 15.48 22.34 17 14 5.32 16.6 22.40 16 15 6.4 16.23 22.47 15 16 6.19 16.41 22.53 14 17 6.42 16.58 22.59 13 18 7.5 17.15 23.4 12 19 7. â—8 17.32 23.9 11 20 7. â—0 17.48 23.13 10 21 8.13 18.4 23.17 9 22 8.35 18.19 23.20 8 23 9.10 18.35 23.33 7 24 9.21 18.50 23.25 6 25 9.42 19.5 23.28 5 26 10.4 19.19 23.29 4 27 10.26 19.33 23.30 3 28 10.48 19.47 23.30 2 29 11.9 20.00 23 31 1 30 11.31 20.13 23.31 0 degrees d. m. d. m. d. m. degrees ♓ â™ â™’ ♌ ♑ ♋ The use of this Table This Table consisteth of 5 Columns the first and last contain the degrees of the Signes that are placed in the head or foot thereof that if you find the sign that the Sun is in at the head or foot of the Table and the degrees in the first or last Column thereof then at the intersection you will have the Suns declination Example Let the Suns place be 20 degrees in Taurus or Scorpio to find the Suns declination you must find Taurus or Scorpio in the head of the Table and 20 degrees on the first Column then guide your eye from ♉ til you come against 20 degr there you shall finde
17 degr and 48 m. the Suns declination when he is 20 deg in ♉ or â™ Note if you find the Sign in the foot of the Table you must find the degrees in the last Column This Table is of much excellency for the calculating of divers propositions Astronomical for it being one of the three terms given in most Solar propositions as viz. Let the declination of the Sun elevation of the Pole and Suns almicanter be given by which you shall finde viz. The Suns meridian height The Suns place in the ecliptique The length of the day and night The hour of East and West The Azimuth of 6 a clock The Suns Azimuth The right Ascension The oblique Ascension The oblique Descension The Ascensional difference The Amplitude The Semidiurnal arch Example with Illustrations Let there be given the Suns declination 20 degrees and 14 m. then the suns place wil be the first point of Gemini Let there be given the elevation of the Pole 51 degrees 32 min. Let there be given the Suns Almicanter 49 deg which will stand as viz. North Declination 20 deg 14 min. given North Elevation 51 deg 51 min given North Almicanter 49 deg 00 min. given The first operation to find the Suns amplitude say As the complment of the elevation of Pole 38 deg 28 m. 9.79383 To the Suns declination 20 d. 14 m. 9.53888 So is the Radius 50 d. 10.00000 To the amplitude 33 d. 47 m. 9.74505 The second operation to find the ascensional difference say As Radius 90 d. 10.00000 to the amplitude 33 d. 47 9.74511 so is the elevation of the Pole 51 d. 32 m. 9.89383 25 d. 48 m. to the ascensional difference upon a great circle 9.63885 Then substract the declination from 90 and the remainder will be 69 d. 46 m. then say If 69 d. 46 m. upon a great circle 9 97233 will become 90 d. upon a little circle 10.00000 what will 25 d. 48 m. upon a great circle 9.63871 it will give the ascensional difference 27 d. 38 m. a little circle 966668 this 27 d. 38 m. converted into time will be 1 hour 50 min. so long time the Sun hath been above the horizon before 6 a clok The fourth operation is to find the Suns almicâ—nter at 6 a clock say As Radius 90 d. 10.00000 to the Suns declination 20 d. 14 m. 953888 so is the elevation of the Pole 51 d. 32 m. 989374 to the almicanter at 6 a clock 15 d. 43 m. 943262 The fift operation is to find when the Sun will be East and West say then As the elevation of the Pole 51 d. 32 m. 9.89374 to the suns declination 20 d 14 m. 9.53888 so is the complement of the elevation of Pole 9.79383 to the distance of the suns way from 6 a clock to East in a great circle 15. d. 56 m. 9.43897 then substract the declination from Radius and the remainder will be 69 d. 46 m. then say As 69 d. 46 m. upon a great circle 9.97233 will give 90 d. upon a little circle 10.00000 what will 15 d. 56 m. upon a great circle 943857 it will give 17 d. 1 m. upon a little circle 946624 this 17 d. 1 m. being converted into time will be 1 hour 8 m. so long time will the sun be after 6 a clock before he come to be ful East and at night hee will be ful West 1 hour 8 m before 6 a clock The seventh operation is to find the difference of the Almicantâ—r given 49 d. and almicanter found at 6 a clock which difference is found by the natural signs as viz. The sign of the almicanter given 49 d. 754790 The sign of the almicanter of 6 a clock 15.43 270880 The difference of the almicanters 28.56 483829 The eighth operation is to find how far the sun hath swerved from 6 a clock whereby to know the hour of the day say then As the difference of the almicanters 28 d. 56 m. 9.86374 to the complement of the elevation of the Pole 38 d. 28 m. 9.79383 so is the Radius 90 d. 10.00000 to the distance the sun swerved from 6 a clock upon a great circle 50 d. 55 m. 898991 then substract the suns declination from radius then say in the ninth operation If 69 d. 46 m. upon a great circle 997233 wil become 90 d. upon a little circle 10 00000 what wil 50 d. 55 m. great circle become 988999 which is 55 d. 49 m. a little circle 991766 this 55 d. 49 m. being converted into time wil be 3 houres 43 m. which being added to 6 a clock it wil be 9.43 that is to say 9 a clock 43 m. after when the suns almicâ—â— was 49. deg The tenth operation is to find the Suns almicanter when he is East or West say As the elevation of the Pole 51 d. 32 m. to the Suns amplitude 33 d. 47 m. so is the complement of the elevation 38 d. 28 m. to the suns almicanter at Last or West 26 d. 13 m. which take from the almicanter given 49 d. by the natural signs as viz. The almicanter of 49 d. 00 m. 75470 The almicanter of 26 d. 13 m. 441766 The remainder is 18.14 312943 Which is the almicanter made since the sun came from East The twelfth operation is to find the suns azimuth say As the complement of the elevation of the Pole 38 d. 28 m. is to the almicanter since the sun came from East 18 d. 14 m. so is the elevation of the Pole 51 d. 32 m to the suns azimuth upon a great circle 23 d. 11 m. then substract 49 the almicanter given from radius the remainder will be 41 degrees In the thirteenâ—h operation say If 41 d. upon a great circle 9.81694 will become 90 d. upon a little circle 10.00000 what wil 23 d. 11 m. upon a great circle 9.59513 it wil be the suns azimuth 36 d. 52 m. 9.77819 The fourteenth operation to find the suns place as viz. As the suns greatest declination 23 d 31 m. 960099 to the declination in the point of the ecliptique 20 d. 1 m. 953880 so is radius 90 d. 10.000000 to the suns place 60 d or ♊ 993789 The fifteenth operation finde the Suns right ascension as viz. As Radius 90 d. 10.00000 to the tangent of the suns place 60 d. 10.23856 so the cosign of the suns greatest declination 23 d. 31 m. 9.96234 to the tangent of the suns right ascension 57 d. 48 m. 10.20090 To find the suns oblique ascension being he is in the Northern signs substract the ascensional difference 27 d. 38 m. which is found in the second operation from the suns right ascension 57 d. 48 m. and the remainder is 30 d. 10 m. which is the suns oblique ascension If the sun be in Southern signs adde To find the suns oblique descension the sun being in the Northern signs adde the ascensional difference to the right ascension and it will give 85 d. 26 m. the